evaluate
cot[90-theta].sin[90-theta] / sin theta+cot 40/tan 50 - [cos square 20 +cos square 70]
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Answer:
Cot(90° - θ).Sin(90°-θ)/Sinθ + Cot40°/Tan50° - (Cos²20° + Cos²70°) = 1
Step-by-step explanation:
evaluate
cot[90-theta].sin[90-theta] / sin theta+cot 40/tan 50 - [cos square 20 +cos square 70]
Cot(90° - θ).Sin(90°-θ)/Sinθ + Cot40°/Tan50° - (Cos²20° + Cos²70°)
Cot(90° - θ) = Cos(90°-θ)/Sin(90°-θ)
=> Cot(90° - θ).Sin(90°-θ) = (Cos(90°-θ)/Sin(90°-θ)) * Sin(90°-θ)
=> Cot(90° - θ).Sin(90°-θ) = Cos(90°-θ)
Cot(90 - θ) = Tanθ => Cot40° = Cot(90° - 50°) = tan50°
Cos(90-θ) = Sinθ => Cos20° = Cos(90° - 70°) = Sin(70°)
Using all these
= Sinθ/Sinθ + tan50°/Tan50° - (Sin²70° + Cos²70°)
= 1 + 1 - 1 ( using sin²θ + Cos²θ = 1)
= 1
Cot(90° - θ).Sin(90°-θ)/Sinθ + Cot40°/Tan50° - (Cos²20° + Cos²70°) = 1
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