Question

Evaluate cube root of 0.027 upon 0.008 / square root of 0.09 upon 0.04 -1

Answer 1

you mean, we have to evaluate $\frac{\sqrt[3]{\frac{0.027}{0.008}}}{\sqrt{\frac{0.09}{0.04}}-1}$

first of resolve all the given terms ,

0.027 = 27/1000 = (3 × 3 × 3)/(10 × 10 × 10) = 3³/10³ = (3/10)³ = (0.3)³

0.008 = 8/1000 = (2 × 2 × 2)/(10 × 10 × 10) = 2³/10³ = (2/10)³ = (0.2)³

0.09 = 9/100 = (3 × 3)/(10 × 10) = (3/10)² = (0.3)²

0.04 = 4/100 = (2 × 2)/(10 × 10) = (2/10)²

= (0.2)²

now, $\sqrt[3]{\frac{0.027}{0.08}}=\sqrt[3]{\frac{(0.3)^3}{(0.2)^3}}$

= $\frac{0.3}{0.2}=1.5$

and $\sqrt{\frac{0.09}{0.04}}=\sqrt{\frac{(0.3)^2}{(0.2)^2}}$

= $\frac{0.3}{0.2}=1.5$

so, $\frac{\sqrt[3]{\frac{0.027}{0.008}}}{\sqrt{\frac{0.09}{0.04}}-1}$

= 1.5/(1.5 - 1)

= 1.5/0.5

= 3

hence, answer is 3.

Answer 2

Answer:

The answer is 0 , I beat

Step-by-step explanation: