Question

Evaluate \dfrac c2-3+\dfrac 6d 2 c ​ −3+ d 6 ​ when c=14c=14 and d=3d=3.

Answer 1

Solution:

We have to evaluate the expression when, c=14, d=3

$\frac{c}{2}-3+\frac{6}{d} (2c-3)+ d ^6\\\\= \frac{14}{2}-3+\frac{6}{3}(2 \times 14-3)+3^6\\\\=7-3+2(28-3)+729\\\\ =4+2 \times 25+729\\\\ =4 +50 +759\\\\=813$

Answer 2

The evaluation is $\frac{c}{2}-3+\frac{6}{d}=6$

Step-by-step explanation:

Given : Expression $\frac{c}{2}-3+\frac{6}{d}$ when c=14 and d=3.

To find : Evaluate the expression ?

Solution :

Expression $\frac{c}{2}-3+\frac{6}{d}$

Substitute c=14 and d=3 in the expression,

$\frac{c}{2}-3+\frac{6}{d}=\frac{14}{2}-3+\frac{6}{3}$

$\frac{c}{2}-3+\frac{6}{d}=7-3+2$

$\frac{c}{2}-3+\frac{6}{d}=6$

Therefore, the evaluation is $\frac{c}{2}-3+\frac{6}{d}=6$

#Learn more

$\dfrac{3x}{2}+\dfrac{5}{8}=\dfrac{2}{5}\:\\\\ find \: x$

https://brainly.in/question/9284246