Question

evaluate double integral of xdydx,x=0 to x=1,y=x^2 to y=2-x​

Answer 1

Answer:

X = 0

Intergal = 0

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X = 1

Intergal = X

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Y= X²

Intergal = $\frac{X{} ^{3}}{3}$

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Y = 2 - X

Intergal = $2X - \frac{X {}^{2} }{2}$

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