Question

Pls answer answer....??then the angle of projection is?​

Answer 1

Given :-

Initial Velocity = 0 m/s

Acceleration = 10 m/s²

As we know about the

Equation of Trajectory

y = xtanØ+ gx²/2u²cos²Ø

Now we will equate this equation in the question,

y = √3x - x²

xtanØ + gx²/2u²cos²Ø = √3x - x²

xtanØ = √3x

tanØ = √3

tanØ = tan 60°

Ø = 60°

Here the particle is projected with an angle of 60°.