evaluate dy/dx when x=2
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dy/dx= d/dx(a+bx²) / x²
=> dy/dx= d/dx(a/x²) +d/dx(bx²/x²)
= -a/x +b
I think it may help you..
IF IT IS CORRECT PLEASE MARK IT AS A BRAINLIEST ANSWER..
=> dy/dx= d/dx(a/x²) +d/dx(bx²/x²)
= -a/x +b
I think it may help you..
IF IT IS CORRECT PLEASE MARK IT AS A BRAINLIEST ANSWER..
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