Evaluate:-
i) Sinx/2n
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Answer:Since (sin x)2 is almost always less than 1, when it is raised to the n→∞ power it will get closer and closer to 0.
The only places where this does not happen is when (sin x)2 = 1 in which case 1 raised to the n→∞ power is still 1.
So the function is equal to 0 everywhere except at specific x values where it is 1, these are the discontinuities.
Specifically, the discontinuities, f(x)=1, are when sin(x) = +/-1, that is when
x = 90 degrees + m*180 degrees
with m = ...,-3,-2,-1,0,-1,2,3,...
Or, as is more common in/beyond precalc,
x is in radians (π radians = 180 degrees) and the discontinuities are then at:
x = π/2 + m*π
Step-by-step explanation:
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