Question

find the product of (a^2b-2)(5-ab^2)​

Answer 1

Answer:

${\huge{\blue{\boxed{\red{\ulcorner{\mid{\overline{\underline{\bf{Solution:-}}}}}}\mid}}}}$

$Method I</p><p></p><p>Given that, a-2b=15a−2b=15</p><p>:. (a-2b)^2=15^2=225.</p><p>:. a^2-2*a*2b+4b^2=225, i.e., a^2-4ab+4b^2=225.</p><p></p><p>Letting, ab=11 in this, we have, a^2-4(11)+4b^2=225.</p><p></p><p>Hence, a^2+4b^2=225+44=269.</p><p></p><p>Method II</p><p></p><p>Notice that (a+2b)^2+(a-2b)^2=2(a^2+4b^2).</p><p></p><p>Here, we replace (a+2b)^2 by (a-2b)^2+8ab, to get,</p><p></p><p>(a-2b)^2+8ab+(a-2b)^2=2(a^2+4b^2),. & now putting the given values,</p><p></p><p>225+8*11+225=2(a^2+4b^2)=538, so, (a^2+4b^2)=538/2=269, as before!</p><p></p><p>$

Answer 2

Answer:

hope it help uh dear!! ☺✌