Question

Evaluate: [i²⁹ + (1/i)⁵⁰]​

Answer 1

Step-by-step explanation:

[ i²⁹ + 1/i⁵⁰]

[ i²⁸ i + 1/(i⁴⁸ i²)]

[ (1)(i) + 1/(1)(i²)] (i⁴k = 1)

[i+1/i²]

[i+(-1)] ( i² = -1)

answer is i -1

Answer 2

• [1²⁹ + (1/i)⁵⁰]

= [1²⁹ i + 1/(1⁴⁸ 1²)]

= [ (1)(i) + 1/(1)(i²)] (i⁴k = 1)

= [i+1/1²]

= [i+(-1)] (i² = - 1)

So, correct answer is i-1.