Question

Evaluate integral 0 to pi/2 dx /1+√cot x​

Answer 1

Answer:

0

π4

π

4

π2

π

2

π

Step-by-step explanation:I=∫π/20sinx‾‾‾‾√(sinx‾‾‾‾√+cosx‾‾‾‾‾√)dx

I

=

∫

0

π

/

2

sin

x

(

sin

x

+

cos

x

)

d

x

.

Answer 2

Answer:

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Step-by-step explanation:

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6

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