Question

evaluate integral root 1+sin2x dx​

Answer 1

Answer:

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Answer 2

Answer:

$∫ \sqrt{1} + sin2x \: dx \\ \\ ∫ {1}^{ \frac{1}{2} } + sin2x \: dx \\ \\ integrate \: w.t.x \\ \\ \sqrt{1} x - \frac{cos2x}{2} + c$