Question

evaluate integration x2+4/x4+x2+16

Answer 1

Answer:

Step-by-step explanation:

Answer 2

∴ The answer is  $\frac{2}{3}x^{3}-\frac{4}{3x^{3} }+16x+c$

Step-by-step explanation:

Given;

$\int (x^{2} +\frac{4}{x^{4} } +x^{2} +16)dx=?$

$=2\int x^{2} dx+4\int{x^{-4}dx+16\int dx$

$=2\frac{x^{3} }{3} +4\frac{x^{-4+1} }{-4+1} +16x+c$   (∵$\int x^{n}dx=\frac{x^{n+1} }{n+1} +c$)

$=\frac{2}{3}x^{3}-\frac{4}{3x^{3} }+16x+c$

Thus, the answer is  $\frac{2}{3}x^{3}-\frac{4}{3x^{3} }+16x+c$