EVALUATE ISING IDENTITY (please solve this)
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Answer:
(2x+y)(2x_y)
(a_b)2
(2x_y)^2
4x_y^2
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(2x+y) (2x-y)
Using the identity (a+b)(a-b) = a² - b²
Here , a = 2x and b=y
so , (2x+y)(2x-y)
= (2x)² -(y)²
= 4x² - y²
Check without using Identity:
(2x+y)(2x-y)
= 2x(2x-y) +y(2x-y)
= 4x² - 2xy + 2xy - y²
= 4x² - y²
Some other identities:
★ (a+b)² = a² + b² + 2ab
★ (a-b)² = a² + b² -2ab
★ (a+b+c)² = a² + b² + c² + 2ab + 2bc +2ca
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