Math, asked by aryash7318, 3 months ago

EVALUATE :- (iv) [4^2 - 3^2] ÷ ( 1 / 7 )^2​

Answers

Answered by ak54384338
1

Answer:

343

Step-by-step explanation:

=[4²-3²]×

=[16-9]×7²

=[7]×7²

=7×7×7

=343

Answered by Anonymous
2

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EVALUATE :- (iv)  [4² - 3²] ÷ {(\frac{1}{7} )}^{2}

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  {4}^{2}  -  {3}^{2}  \div  {(\frac{1}{7}) }^{2}

 = 16 - 9 \div  \frac{1}{49}

 = 7 \div  \frac{1}{49}

 = 7 \times  \frac{49}{1}

 = 7 \times 49

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