Evaluate: lim θ→0 (sin2θ + sin3θ)/2θ + sin3θ
Answers
Answered by
2
Answer:
We will use the Identity
:
sin
2
θ
=
2
sin
θ
cos
θ
Note that,
1
−
cos
θ
sin
2
θ
=
{
1
−
cos
θ
sin
2
θ
}
{
1
+
cos
θ
1
+
cos
θ
}
=
1
−
cos
2
θ
(
sin
2
θ
)
(
1
+
cos
θ
)
=
sin
2
θ
(
2
sin
θ
cos
θ
)
(
1
+
cos
θ
)
=
sin
θ
2
cos
θ
(
1
+
cos
θ
)
=
sin
0
(
2
)
(
cos
0
)
(
1
+
cos
0
)
=
0
4
∴
the Reqd. Lim.=
0
Answered by
1
Answer:
(sin 20 + sin 30) gives sin 30 +cos 10
hope it will help you
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