Evaluate: lim x tends to 4 x⁴ - 64x ÷ √x²+9 - 5
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Given : Lim x→4 (x⁴ - 64x )/(√(x²+9) - 5 )
To Find : Evaluate
Solution:
Lim x→4 (x⁴ - 64x )/(√(x²+9) - 5 )
Put x = 4
= (4⁴ - 64*4 )/(√(4²+9) - 5 )
= (256 - 256)/ (√25 - 5)
= 0/(5 - 5)
= 0/0
as its 0/0 form
we can apply L'hospital Rule
(x⁴ - 64x )/(√(x²+9) - 5 )
= (4x³ - 64) /(2x/2√(x²+9) )
= 4(x³ - 16)√(x²+9)/x
x = 4
= 4(4³ - 16) √(4²+9)/4
= (64 - 16)√25
= 48(5)
= 240
Lim x→4 (x⁴ - 64x )/(√(x²+9) - 5 ) = 240
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