Math, asked by ashutosh144, 1 year ago

evaluate lim xtends to 0 1-cosax/1-cosbx

Answers

Answered by Reetkaur111
2
limx→01−cosax1−cosbx
Here we can write the given limits as;
limax→01−cosaxax×ax×limax→0bx1−cosbx×1bx= axbx×limax→01−cosaxax×limax→0bx1−cosbx=0 .............{Since limx→01−cosxx = 0}
Therefore, limx→01−cosax1−cosbx = 0
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