Question

evaluate limit x tends to zero (cosx-1/x^2)​

Answer 1

limit (cosx-1)/x^2

x__0

while putting the value of X we get 0/0 form so using L hospital rule

( diffrenciating function f(x) and g(x) where f(x)=cosx-1 and g(x) = x^2

lim(_sin x)/2x

x___0

again 0/0 form so again diffrenciating using L hospital rule

lim(-cos x/2)

x__0

so ans is -1/2