Question

evaluate: log (15÷16)+log (64÷81)-log (20÷27)

Answer 1

$log( \frac{15}{16} ) + log( \frac{64}{81} ) - log( \frac{20}{27} ) \\ log(15) - log(16) + log(64) - log(81) - log(20) + log(27) \\ log(15) - 4 log(2) + 6 log(2) - 4 log(3 ) - log(5) - 2 log(2) + 3 log(3) \\ 0$
0 is the answer.