Question

if 4 times the 4th number term of the ap equal to 18times its 18th term then find its 22nd term

Answer 1

▶ Given :-

→ 4(a₄ )  = 18 (a₁₈ ) .

▶ To find :-

→ a₂₂  .

Solution :-

We have,

=> 4(a₄)  = 18 (a₁₈ ) .

=> 4( a + 3d ) = 18( a + 17d ) .

=> 4a + 12d = 18a + 306d .

=> 18a - 4a = 12d - 306d .

=> 14a = - 294d .

=> 14a + 294d = 0 .

=> 14( a + 21d ) = 0 .

=> a + 21d = 0/14 .

=> a + ( 22 - 1 )d = 0.

∴ a₂₂ = 0 .

✔✔ Hence, it is proved ✅✅.

THANKS

#BeBrainly.

Answer 2

here is your answer OK ☺☺☺☺☺

given in this question....

= 4 = 18

= 4( a + 3d ) = 18( a + 17d ) .

=4a + 12d = 18a + 306d .

= 18a - 4a = 12d - 306d .

=14a = - 294d .

= 14a + 294d = 0 .

= 14( a + 21d ) = 0 .

=a + 21d = 0/14 .

= a + ( 22 - 1 )d = 0.

so answer a‹22 = 0