evaluate:log 8 to the base 5 /log 16 to the base 25*log 10 to the base 100
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Use the basic property of logarithm
loga base b= loga/logb
log(a)•^k base b= k*( loga/logb)
So , log5 base 3 = log5/log3
log 27 base 25= (log 27/log25)= (3*log 3)/(2* log 5)
So according to question
(log 5)/( log 3) *( 3/2)* ( log 3)/ (log 5 )
=3/2
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