Evaluate Lt x<0 sin2x .(e³x-1)
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Explanation:
Explanation:
The limit:
lim
x
→
0
sin
(
2
x
)
x
is in the indeterminate form
0
0
so we can solve it using l'Hospital's rule:
lim
x
→
0
sin
(
2
x
)
x
=
lim
x
→
0
d
d
x
sin
(
2
x
)
d
d
x
x
=
lim
x
→
0
2
cos
(
2
x
)
1
=
2
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