Evaluate (p^2 + q^2)x = pq
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Answered by
3
Answer:
x = pq/(p^2 + q^2)
cause i don't see any other options here
Answered by
0
Answer:
p2−q2)/(p2+q2) , dividing both numerator and denominator by q2,
= [p/q)2−1]/[(p/q)2+1]
=[(x+3/x−3)2−1]/[(x+3/x−3)2+1]
=[(x+3)2−(x−3)2]/[(x+3)2+(x−3)2]
= 12x/(2x2+18)
=6x/(x2+9)
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