Question

evaluate..question from trignometry​

Answer 1

Answer:

The answer will be 1

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Answer 2

Answer:

$\cos(90 - \infty ) = \sin( \alpha )$

$\csc( \alpha ) = \frac{1}{ \sin( \alpha ) }$

$\tan(90 - \alpha ) = \cot( \alpha )$

$\tan( \alpha ) = \frac{1}{ \cot( \alpha ) }$

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