Math, asked by Amandj1234, 1 year ago

Factorise this (5a+2)^2-(2a-1)^2

Answers

Answered by sathvikareddy8573
1

Answer:

hope this answer may help you

Attachments:
Answered by TRISHNADEVI
2

 \huge{ \underline{ \overline{ \mid{ \mathfrak{ \purple{ \:   \: SOLUTION \:  \: } \mid}}}}}

FORMULA USED :-

 \:  \:  \:  \:  \:  \:  \boxed{ \bold{ \:  \: x {}^{2}  + y {}^{2}  = (x + y)(x - y) \:  \: }}

 \:  \:  \:  \:  \mathtt{(5a + 2) {}^{2}  - (2a - 1) {}^{2} } \\  \\  \mathtt{ = [(5a + 2) + (2a - 1)][(5a + 2) - (2a - 1)]} \\  \\  \mathtt{ = (5a + 2 + 2a - 1)(5a + 2 - 2a + 1)} \\  \\  \mathtt{ = (7a + 1)(3a + 3)}

Again,

\mathtt{ (7a + 1)(3a + 3)} \\  \\ \mathtt{ = 7a(3a + 3) + 1(3a + 3)} \\  \\  \mathtt{ = 21a {}^{2} + 21a + 3a + 3 } \\  \\  \mathtt{ = 21a {}^{2} + 24a + 3 }

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