evaluate (root5 + 2 root2)sq - (root5 - root8)sq
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Answered by
7
√8 = 2√2 only...
So,
(√5 + 2√2)² - (√5 - 2√2)² is much like a²-b² right? Where a = (√5 + 2√2) and b = (√5 - 2√2)
We know a²-b² = (a+b)(a-b)...
Answer : (√5)(4√2) = 4√10
So,
(√5 + 2√2)² - (√5 - 2√2)² is much like a²-b² right? Where a = (√5 + 2√2) and b = (√5 - 2√2)
We know a²-b² = (a+b)(a-b)...
Answer : (√5)(4√2) = 4√10
krish160502:
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Answered by
3
√8 = 2√2 only...
So,
(√5 + 2√2)² - (√5 - 2√2)² is much like a²-b² right? Where a = (√5 + 2√2) and b = (√5 - 2√2)
We know a²-b² = (a+b)(a-b)...
Answer : (√5)(4√2) = 4√10
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