Question

Evaluate
S2
x sinx dx​

Answer 1

Answer:

I=∫e

x

sinxdx

By using integration by parts

I=e

x

(−cosx)−∫e

x

(−cosx)dx

=−e

x

cosx+∫e

x

(cosx)dx

Again evaluate 2± Integral by parts

we get

I=−e

x

cosx+e

x

sinx−∫e

x

sinxdx

I=−e

x

cosx+e

x

sinx−I

2I=e

x

(sinx−cosx)+c

I=

2

e

x

(sinx−cosx)+c

Explanation:

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