Question

Evaluate sec 13°÷cosec 77°♧+cosec 15°÷sec75°​

Answer 1

$\frac{sec 13 }{cosec 77} + \frac{cosec 15 }{sec 75 } \\= \frac{sec (90-77) }{cosec 77} + \frac{cosec (90-75) }{sec 75 } \\= \frac{cosec 77}{cosec 77} + \frac{sec 75 }{sec 75 } \\= 1 + 1 \\= 2$

Therefore.,

$\red{ \frac{sec 13 }{cosec 77} + \frac{cosec 15 }{sec 75 }} \green { = 2 }$

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