Evaluate (sec 41 sin 49 + cos 29 cosec 61 ) -[ 2/root 3 (tan 20 tan 60 tan 30 / 3( sin 2 31 sin 2 59)]
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sec 41 = cosec(90 -41) = cosec 49
cos 29 = sin(90- 29) = sin 61
we know sin A * cosec A = 1
sin59 = cos(90-59) = cos 31
we know that sin A * cosA = 1/2 * sin2A
tan 60 = cot(90-60) = cot30 = 1/tan30
so given: ( 1 + 1) - [ 2/√3 (tan20 * 1) / 3 (sin^2 62 /4) ]
= 2 - [ 8 * tan 20 / (3√3 sin² 62) ]
= 1.28....
cos 29 = sin(90- 29) = sin 61
we know sin A * cosec A = 1
sin59 = cos(90-59) = cos 31
we know that sin A * cosA = 1/2 * sin2A
tan 60 = cot(90-60) = cot30 = 1/tan30
so given: ( 1 + 1) - [ 2/√3 (tan20 * 1) / 3 (sin^2 62 /4) ]
= 2 - [ 8 * tan 20 / (3√3 sin² 62) ]
= 1.28....
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