Question

Evaluate sec^4A-sec^2=tan^4+tan2A​

Answer 1

Hi !

From LHS

Given that , sec⁴¢ - sec²¢

sec²¢ ( sec²¢ - 1 )

sec²¢ ( tan²¢)

(1+ tan²¢ ) tan²¢

tan²¢ + tan⁴¢ Proved LHS = RHS ,.

Used formula, = sec²¢ - 1 = tan²¢

__________________________

Hope it's helpful

Answer 2

Step-by-step explanation:

refer to this attachment ✅✅