Evaluate (secA+ tanA) (1- sinA)
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Heya!!
Sec A + Tan A = ( 1 + Sin A ) / Cos A
_______________________________
=>
( 1 + Sin A ) × ( 1 - Sin A )
_________________________
Cos ( A )
=>
( 1² - Sin² A )
____________
Cos ( A )
=>
Cos² A
_______
Cos A
= Cos A
Sec A + Tan A = ( 1 + Sin A ) / Cos A
_______________________________
=>
( 1 + Sin A ) × ( 1 - Sin A )
_________________________
Cos ( A )
=>
( 1² - Sin² A )
____________
Cos ( A )
=>
Cos² A
_______
Cos A
= Cos A
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