evaluate sin(-11pi/3)
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Answered by
54
sin(-11pi/3)
=sin(-4pi+pi/3)
=sin(pi/3)
=sin60degree
=root3/2
=sin(-4pi+pi/3)
=sin(pi/3)
=sin60degree
=root3/2
Answered by
63
[tex]sin( -\frac{11\pi}{3} ) = -sin( \frac{11\pi}{3} ) = -sin( \frac{12\pi}{3}- \frac{\pi}{3} ) \\ \\
=-sin(4\pi-\frac{\pi}{3}) = -sin(- \frac{\pi}{3} ) = sin(\frac{\pi}{3}) = \frac{ \sqrt{3} }{2} [/tex]
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