Question

evaluate sin^2 75 -sin^2 15

Answer 1

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Answer 2

Answer:

$Value\: of \:sin^{2}75-sin^{2}15=\frac{3}{4}$

Step-by-step explanation:

Given sin²75°- sin²15°

= sin²(90°-15°)-sin²15°

= cos²15°-sin²15°

/* sin(90-x) = cosx */

= cos (2×15°)

/* cos²x-sin²x = cos2x */

= cos² 30°

= $\left(\frac{\sqrt{3}}{2}\right)^{2}$

= $\frac{3}{4}$

Therefore,

$Value\: of \:sin^{2}75-sin^{2}15=\frac{3}{4}$

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