Question

Evaluate:sin 41°.sec49°+sin57/cos33

Answer 1

sin41° can be written as cos 49°

sec49° can be written as 1/cos49°

So sin41°.sec49°=cos49°.1/cos49° = 1

now

sin57° can be written as cos 33°

according to the Question

sin57°/co33° = cos33°/cos33° = 1

so according to the Question

sin41°.sec49°+sin57°/co33°

= 1 + 1

=2