Question

evaluate sin 58 / cos 32 + tan 42 / cot 48

Answer 1

sin(90-32)/cos32 + tan(90-48)/cot48,

cos32/cos32 + cot48/cot48,

1 + 1,

2

Answer 2

$\frac{\sin 58}{\cos 32}+\frac{\tan 42}{\cot 48}=2$

Step-by-step explanation:

Given : Expression $\frac{\sin 58}{\cos 32}+\frac{\tan 42}{\cot 48}$

To find : Evaluate the expression ?

Solution :

Expression $\frac{\sin 58}{\cos 32}+\frac{\tan 42}{\cot 48}$

Re-write it as,

$=\frac{\sin (90-32)}{\cos 32}+\frac{\tan (90-48)}{\cot 48}$

Applying trigonometric identities,

$\sin(90-\theta)=\cos \theta$

$\tan(90-\theta)=\cot \theta$

$=\frac{\cos 32}{\cos 32}+\frac{\cot 48)}{\cot 48}$

$=1+1$

$=2$

Therefore, $\frac{\sin 58}{\cos 32}+\frac{\tan 42}{\cot 48}=2$

#Learn more

Evaluate: (cos^2 32° + cos^2 58°)/(sin^2 59° + sin^2 31°)

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