Question

evaluate
(sin 66/2 cos 34) +(2 sec 43/ cosec47)​

Answer 1

Answer:

3/2

Step-by-step explanation:

(sin 66/2 cos{90-66]) + (2 sin 47/ cos43)

(sin 66/ 2 sin66) + (2 sin 47/cos(90-47))

(1/2)+(2)

5/2

Formula to remember => sin (90-x) = cos x

                                           cos (90-x) = sin x

Answer 2

Step-by-step explanation:

sin 66/2 cos 24) +(2 sec 43/ cosec47

=sin(90-24)/2 cos 24+2 sec (90-47)/ cosec 47

=cos 24/2 cos 24 +2 cosec 47/cosec 47

=1/2+2=5/2

hope my answer will satisfy you....