evaluate
(sin 66/2 cos 34) +(2 sec 43/ cosec47)
Answers
Answered by
4
Answer:
3/2
Step-by-step explanation:
(sin 66/2 cos{90-66]) + (2 sin 47/ cos43)
(sin 66/ 2 sin66) + (2 sin 47/cos(90-47))
(1/2)+(2)
5/2
Formula to remember => sin (90-x) = cos x
cos (90-x) = sin x
Answered by
2
Step-by-step explanation:
sin 66/2 cos 24) +(2 sec 43/ cosec47
=sin(90-24)/2 cos 24+2 sec (90-47)/ cosec 47
=cos 24/2 cos 24 +2 cosec 47/cosec 47
=1/2+2=5/2
hope my answer will satisfy you....
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