Question

Evaluate
sin 75° - sin 15°
cos 75° +cos 15​

Answer 1

Step-by-step explanation:

I think this is the right answer of the question

Answer 2

sin(A-B)=sinAcosB-cosAsinB

cos(A+B)=cosAcosB-sinAsinB

sin(A+B)=sinAcosB+cosAsinB

cos(A-B)=cosAcosB+sinAsinB

sin75=sin(45+30)=sin45cos30+cos45sin30

=1/_/2 × _/3/2+1/_/2 × 1/2=_/3+1/2_/2

sin15=sin(45-30)=sin45cos30-cos45sin30

=1/_/2×_/3/2-1/_/2×1/2=_/3-1/2_/2

sin75-cos15=_/3+1/2_/2-[_/3-1/2_/2]=2/2_/2=1/_/2

answer for first question 1byroot2

using the given identities you can solve next question also