Math, asked by idknanmollaa, 2 months ago

Evaluate:
sin 77° cos77°
2
+
cos13° sin13°
20)2 – 2cos245°

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Answers

Answered by Rejinabhatta

0

= (sin77°/sin13°)²+(cos77°/sin13°)²-2cos²45°

= (0.98/0.22)²+(0.22/0.22)²-2*0.5

= 19.84+1-1

= 19.84

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