Math, asked by bhallaamulya2107, 1 year ago

Evaluate : (sin 90^o/cos 45^o) + (1/cosec 30^o)

Answers

Answered by shpriyanshu
0
(1/1/√2) + (1/2)

√2 + 1/2

(2√2+1)/2
Answered by DeeptiMohanty
1
Here is your answer....

= ( sin90°/cos45° ) + ( 1/ cosec 30°)

sin 90° = 1

cos 45° = 1/√2

cosec 30° = 2

Now putting this values in the given equation..
we get,

 =  \frac{1}{ \frac{1}{ \sqrt{2} } }  +  \frac{1}{2}  \\  \\  =  \sqrt{2}  +  \frac{1}{2}
Hope this helps you....✌✌


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