Math, asked by raotd, 3 months ago

Evaluate :(sinΘ+cosΘ)²+(cosΘ-sinΘ)²

Answers

Answered by yashaswini3679
7

(sin θ + cos θ)² + (cos θ - sin θ)²

sin² θ + cos² θ + 2sinθ cos θ + cos² θ + sin² θ - 2sin θ cosθ

2(sin² θ + cos²θ)

2(1)

2

Answered by prachisonups
0

Answer

= (sinθ + cosθ)² + (sinθ - cosθ)²

= sin²θ + cos²θ + 2 sinθ cosθ + sin²θ + cos²θ - 2 sinθ cosθ

= 1 + 1 ,  since sin²θ + cos²θ = 1

= 2

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