Question

evaluate sin raise to 6 theta + cos raise to 6 theta

Answer 1

Consider, sin6ө�+�cos6ө =1-3sin2өcos2ө ( sin2ө)3�+�(cos2ө)3�= (sin2ө�+�cos2ө)3� − 3 (sin2ө cos2ө)(sin2ө�+�cos2ө)�� [since a + b = (a+b)3�− 3ab(a+b)]

Answer 2

(sin2ө)3+(cos2ө)3= (sin2ө+cos2ө)3− 3 (sin2ө cos2ө)(sin2ө+cos2ө) [since a + b = (a+b)3− 3ab(a+b)]= 1 − 3sin2өcos2ө [Since sin2ө+cos2ө = 1]