Math, asked by johnstone1971english, 7 hours ago

Evaluate= Sin² 36°+sin² 27°/cos² 17°+cos² 73°​

Answers

Answered by harini27042004
1

Answer:

Given,

cos

2

17+cos

2

73

sin

2

63+sin

2

27

=

cos

2

(17)+(cos(90−17))

2

sin

2

63+(sin(90−63))

2

As we know

90−63=27

90−17=73

from (sin(90−63)=cos63, cos(90−17)=sin17,

Now,

cos

2

17+cos

2

73

sin

2

63+sin

2

27

=

cos

2

(17)+(cos(90−17))

2

sin

2

63+(sin(90−63))

2

=

cos

2

17+sin

2

17

sin

2

63+cos

2

63

=

1

1

=1 ∵sin

2

A+cos

2

  • A=1

Answered by Anonymous
1

Answer:

answer (1)

Step-by-step explanation:

cos²27°+sin²27°/sin²73°+cos²73

(using sin²A+cos²A)

=> 1/1

1

Similar questions