evaluate sin2x+cosx
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ꜱɪɴ2x = 2 ꜱɪɴx ᴄᴏꜱx
ꜱɪɴ2x+ᴄᴏꜱx=2 ꜱɪɴx ᴄᴏꜱx+ᴄᴏꜱx
=ᴄᴏꜱx(2ꜱɪɴx+1)
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Answered by
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Answer:
sin2x=2sinx cos x
Step-by-step explanation:
2sinxcosx+cosx
cosx(2sinx+1)
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