Math, asked by angelmarykj426, 1 year ago

evaluate sin2x+cosx​

Answers

Answered by Anonymous
1

ꜱɪɴ2x = 2 ꜱɪɴx ᴄᴏꜱx

ꜱɪɴ2x+ᴄᴏꜱx=2 ꜱɪɴx ᴄᴏꜱx+ᴄᴏꜱx

=ᴄᴏꜱx(2ꜱɪɴx+1)

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Answered by umiko28
1

Answer:

sin2x=2sinx cos x

Step-by-step explanation:

2sinxcosx+cosx

cosx(2sinx+1)

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