Evaluate sinA•cosA, if sinA + cosA=√2
Answers
Answered by
3
Step-by-step explanation:
(sinA+cosA)²=(√2)²
sin²A+cos²A+2sinA.cosA=2
1+2sinA.cosA=2
2sinA.cosA=2-1
sinA.cosA=1/2
Answered by
2
Answer:
The answer to this question is 1/2
Step-by-step explanation:
Given that, sinA+cosA =
Now in order to generate an expression like (sinA.cosA) we are squaring the equation
On squaring both sides of the equation we get,
(sinA+cosA)² = ()²
or, sin²A + cos²A + 2.sinA.cosA = 2 ( ∵ (a+b)² = a²+b²+2ab)
or, 2sinA.cosA = 2-1 ( ∵ sin²A + cos²A = 1 )
or, 2sinA.cosA = 1
or, sinA.cosA = 1/2
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