Question

evaluate sinthetacostheta +sinthetacos(90-theta)costheta/sec(90-theta)+costhetasin(90-theta)sintheta/cosec(90-theta)-2sin(90-theta)cos(90-theta)

Answer 1

sec[90-Ф].sin[90-Ф]+cosec[90-Ф].cos[90-Ф]
cosecФ.cosФ+secФ.sinФ
cosФ/sinФ+sinФ/cosФ
cos²Ф+sin²Ф/[sinФ.cosФ]
1/[sinФ.cosФ]
secФ.cosecФ=R.H.S

hence proved

Answer 2

Hello dear....
Please find your answer in the attachment..