Math, asked by thomasphilipt2892, 1 year ago

Evaluate tan 1 tan 2 tan 3 . . . . Tan 89 = 1

Answers

Answered by Anonymous
7
HEY mate here is your answer.
_______________________________________________________________________________
LHS
=tan 1 tan 2...tan 45 ....tan 88 tan 89
=tan 1 tan 2...tan 43 tan 44 tan 45 cot 44 cot 43...cot 2 cot 1
=tan 45
=1

hence LHS=RHS
_________________________________________________________________________________

hope it helps you.

^_^
Answered by Anonymous
26

Hey there !!


Answer: 1 .



Step-by-step explanation:


= tan 1 . tan 2 . tan 3 ... tan 44 . tan 45 . tan 46 ... tan 87 . tan 88 . tan 89  



= tan 1 . tan 2 . tan 3 ... tan 44 . tan 45 . tan( 90 - 44 ) ... tan (90 - 3 ) . tan ( 90 - 2 ) . tan ( 90 - 1) 



= tan 1 . tan 2  . tan 3 ...tan44 . tan 45 . cot 44 ... cot 3 . cot 2 . cot 1 



= tan 1 . cot 1 . tan 2 . cot 2 . tan 3 . cot 3 ... tan 44 . cot 44 . tan 45 ... tan 89 . cot 89 



= 1 x 1 x 1 x ... 1 x ... x 1 . [ tan 45 = 1 ] .



= 1 .



Hence, it is solved .



THANKS



#BeBrainly .



Similar questions