Math, asked by nikita3234, 1 year ago

Evaluate Tan 2° tan 3° ..... tan 45° ........ tan 87° tan 88°/(3 sin^2 43°+3 sin^2 47°)-2 (sec^2 39° - cot^2 51°)

Answers

Answered by anandssharmappplus
1

Answer:

1/(3 - 2) = 1

Step-by-step explanation:

tan 2°.tan88° = tan 2°.cot 2° = 1

so,tan2°.....tan 88° = 1

3(sin^2 43°+sin^2 47°) = 3.(sin^2 43°+cos^2 43°) = 3

2(sec^2 39° - cot^2 51°) = 2(sec^2 39° - tan^2 39°) = 2

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