Question

evaluate :tan (55degree-thita )-cot(35degree+thita)

Answer 1

Answer:

0

Step-by-step explanation:

tan ( 55° - theta ) - cot ( 35° + theta )

We know that tan A = cot ( 90° - A )

Therefore,

tan ( 55° - theta ) = cot [ 90° - ( 55° - theta ) ] = cot ( 35° + theta )

Hence,

tan ( 55° - theta ) - cot ( 35° + theta )

= cot ( 35° + theta ) - cot ( 35° + theta )

= 0