evaluate tan a = cot B prove that a + b = 90 degree
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in a right angled triangle ,right angled at c
tanA= BC/AC
cotB=BC/AC
data: tanA=cotB
tan(90-A)=cotB
cotA=cotB
AB/Bc=BC/AC
AC^ = BC^
AC=BC
∆ABC is an isosles right angled triangle. amgle opposite to equal sides are equal .
^A=^B= 180°/2=90°/2=45°
so,^A+^B=90°
hence proved
tanA= BC/AC
cotB=BC/AC
data: tanA=cotB
tan(90-A)=cotB
cotA=cotB
AB/Bc=BC/AC
AC^ = BC^
AC=BC
∆ABC is an isosles right angled triangle. amgle opposite to equal sides are equal .
^A=^B= 180°/2=90°/2=45°
so,^A+^B=90°
hence proved
Answered by
2
❤
It is given that
tan A = cot B
⇒tan A=tan (90° −B )
{ °•° cot B = tan ( 90° − B ) }
⇒A = 90° −B
⇒A + B= 90°
Hence Proved
☺
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