Question

evaluate tan65/cot25

Answer 1

Answer:

here

$65 + 25 = 90$

$\cot(25) = \cot(90 - 65) = \tan(65)$

$tan(65 ) \div tan(65) = 1$

Answer 2

Answer:-

$\large\sf{cotA=tan(90°-A)}$

$\large\sf{cot25°=tan(90°-25°=tan65°}$

$\large\sf{i.e.,\frac{tan65°}{cot25°}=\frac{tan65°}{tan65°}=1}$